0=0.5x^2+2x+1.5

Solution for 0=0.5x^2+2x+1.5 equation:

0=0.5x^2+2x+1.5

We move all terms to the left:

0-(0.5x^2+2x+1.5)=0

We add all the numbers together, and all the variables

-(0.5x^2+2x+1.5)=0

We get rid of parentheses

-0.5x^2-2x-1.5=0

a = -0.5; b = -2; c = -1.5;
Δ = b2-4ac
Δ = -22-4·(-0.5)·(-1.5)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-1}{2*-0.5}=\frac{1}{-1}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+1}{2*-0.5}=\frac{3}{-1}
=-3
$